किसी ट्रैन की speed 10 सेकंड में 18kmh से बढ़कर 72 kmh हो जाती है तब दूरी ज्ञात कीजिये
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Given : ट्रैन की speed 10 सेकंड में 18kmh से बढ़कर 72 kmh हो जाती है
To Find : दूरी
Distance travelled
Solution:
U = 18 km/hr = 18 * 5/18 = 5 m/s
V = 72 km/hr = 72 * 5/18 = 20 m/s
V = U + at
=> 20 = 5 + a(10)
=> 15 = a (10)
=> a = 1.5 m/s²
V² - U² = 2aS
=> 20² - 5² = 2(1.5)S
=> 400 - 25 = 3S
=> 375 = 3S
=> 125 = S
Distance travelled = 125 m
दूरी = 125 m
or using
S = ut + (1/2)at²
=> S = 5(10) + (1/2)(1.5)10²
=> S = 50 + 75
=> S = 125 m
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