Question

किसमें Cift चतुर्भुज (i) 11 LF ना 4cm 3cm 2.5 cm Cm (A you cm It Il ucm​

Answer 1

Answer:

Given: AB=3cm, BC=2cm and CA=2.5cm and EF=4cm

Also, △ABC∼△DEF

Thus,

DE

AB

=

EF

BC

=

DF

AC

DE

3

=

4

2

=

DF

2.5

Hence, DE=6cm and DF=5cm

Perimeter of Δ DEF = DE+EF+EF

Perimeter of Δ DEF = 4+5+6

Perimeter of Δ DEF = 15 cm

Explanation:

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