Question

kA uniform rod of mass m is held horizontal by means of two vertical strings at each end as shown in the figure. If the right string is cut, then tension in the left string immediately after the cut is given by

4 n -mg The value of n is.​

Answer 1

Answer:

The total mass of the system is m=2+1+1=4kg

Let a be the acceleration of the system.

Thus, ma=F or 4a=8 or a=2m/s

2

The tension at A is T

A

= mass of left block × acceleration =2×2=4N

and tension at B is T

B

= (mass of left block + mass of string AB)× acceleration =(2+1)×2=6N