Chemistry, asked by tarnnumshamsi, 5 months ago

क्विक लाइम इज एडिट टू व्हाट इस कार्बन डाइऑक्साइड प्रोड्यूस्ड​

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Answered by AkashMathematics
1

Answer:

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5.18 g of copper metal is first converted into copper nitrate and subsequently on ignition to give 6.45 g of CuO. In another experiment, 1.10 g of copper gave 1.37 g of CuO. Show that these data illustrates the law of constant composition.

Case I:

Weight of metal (Cu) = 5.18 g

Weight of metal oxide (CuO) = 6.45 g

Percentage of Cu,

Weight of Copper/Weight of CuO x 100%

= 5.18/6.45 x 100%

= 80.29%

Case II:

Weight of metal (Cu) = 1.10 g

Weight of metal oxide (CuO) = 1.37 g

Percentage of Cu,

Weight of Coppe

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