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5.18 g of copper metal is first converted into copper nitrate and subsequently on ignition to give 6.45 g of CuO. In another experiment, 1.10 g of copper gave 1.37 g of CuO. Show that these data illustrates the law of constant composition.
Case I:
Weight of metal (Cu) = 5.18 g
Weight of metal oxide (CuO) = 6.45 g
Percentage of Cu,
Weight of Copper/Weight of CuO x 100%
= 5.18/6.45 x 100%
= 80.29%
Case II:
Weight of metal (Cu) = 1.10 g
Weight of metal oxide (CuO) = 1.37 g
Percentage of Cu,
Weight of Coppe
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