Question

क्यूबिकल बॉक्स ऑफ 10 पॉइंट 10 सेंटीमीटर​

Answer 1

Answer:

(i) Lateral surface area of cube = 4edge2

[tex].(i) Lateral surface area of cube = 4edge2=4(10)2=400

[tex].(i) Lateral surface area of cube = 4edge2=4(10)2=400lateral surface area of cuboid =2h(l+b)

[tex].(i) Lateral surface area of cube = 4edge2=4(10)2=400lateral surface area of cuboid =2h(l+b)2×8(12.5+10)=16×22.5=360

[tex].(i) Lateral surface area of cube = 4edge2=4(10)2=400lateral surface area of cuboid =2h(l+b)2×8(12.5+10)=16×22.5=360So, the lateral surface area of the cube is larger by (400−360=40)cm2

[tex].(i) Lateral surface area of cube = 4edge2=4(10)2=400lateral surface area of cuboid =2h(l+b)2×8(12.5+10)=16×22.5=360So, the lateral surface area of the cube is larger by (400−360=40)cm2(ii) Total surface area of cube = 6edge2

[tex].(i) Lateral surface area of cube = 4edge2=4(10)2=400lateral surface area of cuboid =2h(l+b)2×8(12.5+10)=16×22.5=360So, the lateral surface area of the cube is larger by (400−360=40)cm2(ii) Total surface area of cube = 6edge2=6(10)2=600

[tex].(i) Lateral surface area of cube = 4edge2=4(10)2=400lateral surface area of cuboid =2h(l+b)2×8(12.5+10)=16×22.5=360So, the lateral surface area of the cube is larger by (400−360=40)cm2(ii) Total surface area of cube = 6edge2=6(10)2=600lateral surface area of cuboid =2(lb+bh+hl)

[tex].(i) Lateral surface area of cube = 4edge2=4(10)2=400lateral surface area of cuboid =2h(l+b)2×8(12.5+10)=16×22.5=360So, the lateral surface area of the cube is larger by (400−360=40)cm2(ii) Total surface area of cube = 6edge2=6(10)2=600lateral surface area of cuboid =2(lb+bh+hl)2(12.5×10+10×8+8×12.5)=2(125+80+100)=610

[tex].(i) Lateral surface area of cube = 4edge2=4(10)2=400lateral surface area of cuboid =2h(l+b)2×8(12.5+10)=16×22.5=360So, the lateral surface area of the cube is larger by (400−360=40)cm2(ii) Total surface area of cube = 6edge2=6(10)2=600lateral surface area of cuboid =2(lb+bh+hl)2(12.5×10+10×8+8×12.5)=2(125+80+100)=610So, the total surface area of cuboid is larger by (610−600=10) cm

[tex].(i) Lateral surface area of cube = 4edge2=4(10)2=400lateral surface area of cuboid =2h(l+b)2×8(12.5+10)=16×22.5=360So, the lateral surface area of the cube is larger by (400−360=40)cm2(ii) Total surface area of cube = 6edge2=6(10)2=600lateral surface area of cuboid =2(lb+bh+hl)2(12.5×10+10×8+8×12.5)=2(125+80+100)=610So, the total surface area of cuboid is large by (610−600=10) cm