Kabir left for patna from madhubani at 8:30am. He travelled at the speed of 60 kmph for 3 hours 15 minutes. After that he reduced the speed to 20 kmph. If the distance between the two cities is 205 km, at what time did kabir reach patna
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Answer:
He reached Patna at 12:15 P.M.
First he travelled for 3 hours 15 minutes at the speed of 60 km/h.
Therefore total distance travelled
=>(60 km/h×3 hours) + (60 km/h+ 15/60 hours)
Which is equal to 180 Km + 15 Km
=195 Km.
Total Distance - Distance travelled = Distance left.
(205-195) Km = 10 Km.
Time Taken = (10÷20) hours.
Time Taken = 0.5 hours or 30 minutes.
Therefore, Total time taken = 3 hours+(15 + 30) Minutes
Total time taken = 3 hours 45 Minutes.
Kabir left Madhubani at = 8:30 A.M.
Kabir reached Patna at = 8:30 A.M. + 3 hours 45 Minutes.
Kabir reached Patna at 12:15 P.M.
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