Kaif is twice as old as sabiha. Five years ago s age was three times sabihas age. Find the present
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hi
let kaif be x and sabhia be y
Kaif is twice as old as sabiha
x = 2y...[1]
Five years ago s age kaif was three times sabihas age.
lets form an euqation
5 - x = 3[5 - y]
now lets put [1] in [2]
since
5 - x = 3[5 - y] and x = 2y
5 - x = 3[5 - y]
5 - 2y = 3[5 - y]
5 - 2y = 15 - y
-2y + y = 15 - 5
y = 10
since x = 2y
=>2 * 10
=>20
hecne kaif is 20 and saif is 10
hope it helps u
:)
let kaif be x and sabhia be y
Kaif is twice as old as sabiha
x = 2y...[1]
Five years ago s age kaif was three times sabihas age.
lets form an euqation
5 - x = 3[5 - y]
now lets put [1] in [2]
since
5 - x = 3[5 - y] and x = 2y
5 - x = 3[5 - y]
5 - 2y = 3[5 - y]
5 - 2y = 15 - y
-2y + y = 15 - 5
y = 10
since x = 2y
=>2 * 10
=>20
hecne kaif is 20 and saif is 10
hope it helps u
:)
muskansethi:
hey please solve my question s
This is correct 100
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