Math, asked by poojaaditipooja4065, 1 year ago

Kaif is twice as old as sabiha. Five years ago s age was three times sabihas age. Find the present

Answers

Answered by Raghav3333
9
hi

let kaif be x and sabhia be y

Kaif is twice as old as sabiha

x = 2y...[1]

Five years ago s age kaif  was three times sabihas age.

lets form an euqation

5 - x = 3[5 - y] 

now lets put [1] in [2]

since 
5 - x = 3[5 - y]   and  x = 2y


5 - x = 3[5 - y] 


5 - 2y = 3[5 - y] 

5 - 2y = 15 - y

-2y + y = 15 - 5

y = 10

since x = 2y

=>2 * 10

=>20

hecne kaif is 20 and saif is 10

hope it helps u

:)

muskansethi: hey please solve my question s
muskansethi: ??
Raghav3333: I solved it yar
This is correct 100
Raghav3333: Saif is twice her age so 10 and 20.five years ago three times her age so . 5 and 15
Raghav3333: Hence present age is 20 and 10
Similar questions