kaise hua explain kar dijiye baar baar ans de rhe h?
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iven,
At, NTP (293 K, 76 cm Hg): Volume,V=22.4L ,Number of mole, n
1
=1mole
273
o
C=546K
At (38 cm, 546 K): Volume V=5.6L
From ideal gas equation.
PV=nRT
P
1
V
2
P
1
V
1
=
n
2
RT
2
n
1
RT
1
⇒
38×5.6
76×22.4
=
n
2
R×546
1×R×293
⇒n
2
=0.67mole
1moleN
2
=28g
0.067moleN
2
=28×0.067=1.87g
Hence, mass of nitrogen is 1.87g
hope it helps very much
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