Math, asked by ashwin133, 1 month ago

Kajal invested a fixed amount of Rs. 80000 in 3 banks A, B and C at 15%, 16% and 27% per annum. The amount invested in Bank A is 20% of the amount invested in Bank C. If she earns the simple interest for 2 years is Rs. 36400 then What is the amount invested in bank B?​p​

Answers

Answered by Anonymous
14

Answer :-

Given:

  • Total amount invested = ₹ 80,000

  • Rate of interest in banks A, B and C = 15%, 16% and 27%

  • Amount invested in Bank A is 20% of amount invested in Bank C

  • Simple interest in 2 years = ₹ 36,400

To find:

  • Amount Invested in Bank B

Solution:

A = \text{$\frac{20}{100}$×C}

C = 5A

Now, let us take the Value of Bank A as x,

Therefore, A = x

C = 5x

B = 80000 - 6x

Interest in 1 year,

Interest on 2 years = ₹ 36400

Interest in 1 year = \frac{36400}{2}=₹18200

Now,

_______________________________________

15% of x + 16% of (80000-6x) + 27% of 5x = 18200

=\frac{15x}{100} + 12800 -\frac{93x}{100} +\frac{95x}{100}=18200 \\ \\ =\frac{15x}{100}-\frac{93x}{100}+\frac{95x}{100}=18200-12800 \\ \\ x=\frac{5400\times{100}}{54} \\ \\ x=10000

________________________________________

Money invested in Bank B = (80000 - 6x)

= (80000 - 60000)

= ₹ 20,000

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