Question

kal submission hai.... doubt in both

Answer 1

sample space is
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
(1) A;doubletof prime no.
P (A); (2,2)(3,3)(5,5) that is 3
P (A);3/36=1/12
(2) B;doublet of odd no.
P (B):(1,1) (3,3)(5,5) that is3
=3/36=1/12





total=500
car=40
scooter=100
bus=160
train=70
cycle=110
no mode of transport =20
(1)=used car and bus

therefore p (a)=40+160=200
200/500 =2/5
(2)=used cycle only
p(b)=110/500=11/50
(3)=no mode of transport
p (c)=20/500=1/25