Question

Kalpna is 3 times
Aarya's agae. Now,

express the followings
through algebra.

(i) their ages after 4
years.

(ii) their ages before 3
years.

( Let Aarya's age= X
years)​

Answer 1

Answer:

here is your answer

if aarya age is X

then Kalpana age=3x

(i) aarya age after 4 years=X+4

Kalpana age after 4 years =3x+4

(ii) aarya age before 3years=x-3

Kalpana age before 3 years=3x-3

HOPE IT HELPS YOU....

Answer 2

Answer

• let's
• kalpna age=3times bigger than aaryas age
• Aaryas age =x
• then ,
• x*3times
• then 3x is the kalpnas age

1. x=3x+4 years

• -4=3x-x
• -4=2x
• x=2+4
• x=6
• then the i equation of Aaryas age is 6years
• then kalpna's age is 6*3
• 6*3=18
• then the kalpna's age is 18years

2.x =3x-3years

• 3=3x-x
• 3=2x
• x=2-3
• x=-1
• then the ii equation of Aaryas age is -1 years
• then the kalpna's age is -3*-1
• -3*-1= 3
• then the kalpna's age is 3

there fore in the i equation

kalpna's age is 18 bigger than the Aaryas age

is 6 years

there fore in the ii equation

kalpna's age is 3 year than the Aaryas age is-1

years

please mark me as brainleist at the down of the solution please