Question

Kamal donated 1/10 of his money to a trust. He gave 1/6 of the remaining money to his wife and divided the remaining money among his four sons. If each son get rupees-60'000. How much did he have?

Answer 1

Step-by-step explanation:

Let his total money be x

money donated to trust=1/10*x=x/10

money given to wife=x/6

remaining amount =x-[(x/10)+(x/6)]

=11x/15

if he had 4 son and each got 60000

total money sons got=240000

remaining amount was given to his son

hence,

11x/15=240000

x=327272.7272727

x is equal to 327272.72 rupees (approx)

Please check the question answer shouldnt be in decimal i think so and mark brainliest

Answer 2

total money Kamal had= Rs. 320000

Step-by-step explanation:

$let \: the \: money \: be \: x$

$he \: donated \: to \: a \: trust = \frac{1}{10} \times x \\ = \frac{x}{10}$

$remaining \: money = x - \frac{x}{10} \\ = \frac{10x - x}{10} \\ = \frac{9x}{10}$

$gave \: to \: wife = \frac{1}{6} \times \frac{9x}{10} \\ = \frac{9x}{60}$

$remaining = \frac{9x}{10} - \frac{9x}{60} \\ = \frac{54x - 9x}{60} \\ = \frac{45x}{60}$

$he \: had = 4 \times 60000 \\ = 240000$

$according \: to \: question \\ \frac{45x}{60} = 240000 \\ 45x = 14400000 \\ x = \frac{14400000}{45} \\ x = 320000$

solved by Longri Rongphar (Asst. Teacher, Tamhidi English School, Tarabasa)