Question

Kamal invested 1/5 of his sum of money at 6%, 1/2 at 5% and the remainder at the rate 10% simple interest. If his annual income is 234.5 then his sum of money is -
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Answer 1

Gɪᴠᴇɴ :-

• Kamal invested at 6% = (1/5) of his sum of money .
• Kamal invested at 5% = (1/2) of his sum of money .
• Kamal invested at 10% = Remaining of his sum of money .
• His Annual income = Rs.234.5 .

Tᴏ Fɪɴᴅ :-

• Total sum of Money kamal Have ?

Sᴏʟᴜᴛɪᴏɴ :-

Let us Assume That, Total sum of Money kamal have is Rs.100x .

Than,

→ invested at 6% = (1/5) * 100x = 20x .

→ invested at 5% = (1/2) * 100x = 50x .

→ invested at 10% = Remaining = 100x - (20x + 50x) = 30x .

→ Time = 1 Year.

→ Simple Interest = ( P * R * T) / 100 .

Putting All Values we get :-

→ (20x * 6 /100) + (50x * 5/100) + (30x * 10/100) = 234.5

→ 120x + 250x + 300x = 234.5 * 100

→ 670x = 23450

→ 67x = 2345

→ x = 35

Hence,

→ Total sum of Money kamal Have = 100x = 100*35 = Rs.3500 (Ans.)

Answer 2

$\rule{200}3$

$\huge\tt{GIVEN:}$

Kamal invested 1/5 of his sum of money at 6%, 1/2 at 5%.

The remainder at the rate 10% simple interest.

His annual income is 234.5.

$\rule{200}3$

$\huge\tt{TO~FIND:}$

The sum of money.

$\rule{200}3$

$\huge\tt{SOLUTION:}$

Let the total sum of money be 100x

Then,

⇝Money Invested at 6% = (1/5 × 100x ) = 20x

⇝Money invested at 5% = (1/2 × 100x ) = 50x

⇝Remaining Money invested at 10% = 100x - (20x + 50x ) = 30x

⇝Time = 1 year

⇝Simple Interest = (P × R × T ) / 100

$\rule{200}3$

So, if we find The SI by putting these values,

➩(20x × 6/100) + (50x × 5/100) + (30x × 10/100) = 234.5

➩120x + 250x + 300x = 234.5 × 100

➩670x = 23450

➩67x = 2345

➩x = 2345/67

➩x = 35

so, the sum is 100x or 100×35 = 3500

$\rule{200}3$