Math, asked by nishu6924, 7 months ago

Kamala borrowed ₹ 26,400 from a Bank to buy a scooter at a rate of 15% per annum compounded yearly. What amount will she pay at the end of 2 years and 4 months to clear the loan?

Answers

Answered by sanvi15122008
25

Solution :-

P = Rs. 26400  

Rate of Interest = 15 %

Time = 2 years and 4 months

In this question, first, we will compute the compounded interest for 2 years.

A = P(1 + R/100)ⁿ

⇒ 26400(1 + 15/100)²

⇒ 26400*115/100*115/100

⇒ A = Rs. 34914  

Now, Simple Interest for 4 months will be calculated and Principal will be Rs. 34914.

Simple Interest = (P*R*T)/100

⇒ (34914*15*4)/(12*100)

⇒ 2094840/1200

⇒ Rs. 1745.7

Total Amount = 34914 + 1745.7

= Rs. 36659.7

Hence, after 2 years and 4 months, Kamala will pay Rs. 36659.7 to clear the loan.

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Answered by Anonymous
12

Step-by-step explanation:

ANSWER

Principal (P) = Rs26,400

Rate (R) = 15% per annum

Number of years (n) = 2124

The amount for 2 years and 4 months can be calculated by first calculating the amount for 2 years using the compound interest formula, and then calculating the simple interest for 4 months on the amount obtained at the end of 2 years.

For calculating amount of first 2 years,

Amount = Principal(1+100R)Time

Interest = Amount - Principal

Amount = 26400(1+10015)2

Amount=34914

Now, the interest for next 31 years will be calculated using Simple Interest

S.I. = 100(P×R×T)

S.I. = 10034914×15×31

S.I. = 1745.70

Therefore, total amount to be paid after 2 years and 4 months = 34,914+1,745.70=Rs 36,659.70

Nearest whole number to 36659.70 is 36660.

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