kamala borrowed rupee 26400 from a bank to buy a scooter at rate of 15% per annum compounded yearly. what amount will she pay at the end of 2 years and 4 months to clear to loan
Answers
Answered by
754
Solution :-
P = Rs. 26400
Rate of Interest = 15 %
Time = 2 years and 4 months
In this question, first, we will compute the compounded interest for 2 years.
A = P(1 + R/100)ⁿ
⇒ 26400(1 + 15/100)²
⇒ 26400*115/100*115/100
⇒ A = Rs. 34914
Now, Simple Interest for 4 months will be calculated and Principal will be Rs. 34914.
Simple Interest = (P*R*T)/100
⇒ (34914*15*4)/(12*100)
⇒ 2094840/1200
⇒ Rs. 1745.7
Total Amount = 34914 + 1745.7
= Rs. 36659.7
Hence, after 2 years and 4 months, Kamala will pay Rs. 36659.7 to clear the loan.
P = Rs. 26400
Rate of Interest = 15 %
Time = 2 years and 4 months
In this question, first, we will compute the compounded interest for 2 years.
A = P(1 + R/100)ⁿ
⇒ 26400(1 + 15/100)²
⇒ 26400*115/100*115/100
⇒ A = Rs. 34914
Now, Simple Interest for 4 months will be calculated and Principal will be Rs. 34914.
Simple Interest = (P*R*T)/100
⇒ (34914*15*4)/(12*100)
⇒ 2094840/1200
⇒ Rs. 1745.7
Total Amount = 34914 + 1745.7
= Rs. 36659.7
Hence, after 2 years and 4 months, Kamala will pay Rs. 36659.7 to clear the loan.
Answered by
326
Given –
Principal (P) = Rs. 26,400,
Time (n) = 2 years 4 months = 2 years 4/12 months = 2 1/3 years
Rate of interest (R) = 15% p.a.
Amount for 2 years (A) = P [(1+r/100)n]
For 2 years,
A = 26400 [1 + 15/100]2
= 26400 [1 + 3/20] 2
= 26400 [23/20] 2
= 26400 x 23/20 x 23/20
= Rs. 34914
For 1/3 years, T = 1/3 years, rate = 15%, P = 34914
Intrest = 34914 X 1 X 15/3X100
= Rs 1745.70
Therefore, Total amount = Rs. 34,914 + Rs. 1,745.70
= Rs 36,659.70
Answer - At the end of 2 years and 4 months to clear to loan Kamala will pay Rs 36,659.70
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