Question

kamlesh buys 2 suitcases at Rs 3690.he sells one at 20% profit and another at 15% loss ,Sp of both suitcases are same. find cost price each suitcase. solve sum​

Answer 1

Answer:

each suit is 3389

Step-by-step explanation:

Answer 2

Answer:

CP of cycle 1 is Rs.640 and CP of cycle 2 is Rs.400.

Step-by-step explanation:

A man bought two cycles for Rs.1040

let the CP of cycle 1 be x

So, CP of cycle 2 = 1040-x

Cycle 1 case:

CP = x

Loss% = 15%

Loss=\frac{15}{100}x=0.15x

100

15

x=0.15x

SP = CP - loss = x-0.15x = 0.85 x

Cycle 2 case:

CP = 1040-x

Profit% = 36%

Profit=\frac{36}{100}(1040-x)

100

36

(1040−x)

SP = CP +Profit =(1040-x)+\frac{36}{100}(1040-x)(1040−x)+

100

36

(1040−x)

Now we are given that each cycle was sold for the same price.

So, 0.85 x=(1040-x)+\frac{36}{100}(1040-x)0.85x=(1040−x)+

100

36

(1040−x)

x=640x=640

So, CP of cycle 1 is Rs.640

CP of cycle 2 = 1040-x = 1040-640 = Rs.400

Hence CP of cycle 1 is Rs.640 and CP of cycle 2 is Rs.400.