Question

Kamlesh spends 80% of his salary and deposits 15 % of his salary in the bank. If he is left with Rs. 1250, what is his monthly salary?​

Answer 1

➤ Given :-

Percent of salary spent :- 80%

Percent of salary deposited :- 15%

Total money left with :- ₹1250

$\:$

➤ To Find :-

The total monthly salary of Kamlesh...

$\:$

★ How to do :-

Here, we are given with the percentage of salary spent and also the percentage of salary deposited in his savings bank. We are also given with the part of salary of Kamlesh after spending and depositing some money by him. We are asked to find the total salary of Kamlesh he get's at one month. So, first we should find the percentage of the money that is done nothing and then, we can find the total salary of Kamlesh with the information of the left over salary percentage and the left over salary. We can also consider the total salary of Kamlesh by any variable say y. Then, we can find the value of that variable y i.e, the total salary by the concept called as transition method. So, let's solve!!

$\:$

➤ Solution :-

Percent of left over salary :-

${\sf \leadsto 100 - (80 + 15)}$

Firstly, add the numbers in bracket.

${\sf \leadsto 100 - 95}$

Subtract the numbers to get the left over salary

${\sf \leadsto 5\%}$

$\:$

Total salary of Kamlesh :-

${\sf \leadsto 5\% \: of \: y = 1250}$

Write the percentage as fraction and 'of' as multiplication sign.

${\sf \leadsto \dfrac{5}{100} \times y = 1250}$

Shift the number on RHS to LHS.

${\sf \leadsto y = \dfrac{1250 \times 100}{5}}$

Write the fraction in lowest form by cancellation method.

${\sf \leadsto y = \dfrac{1250 \times \cancel{100}}{\cancel{5}} = \dfrac{1250 \times 20}{1}}$

Multiply the numbers in numerator.

${\sf \leadsto y = \cancel \dfrac{25000}{1} = 25000}$

$\:$

${\red{\underline{\boxed{\bf So, \: the \: total \: salary \: of \: Kamlesh \: is \: 25000}}}}$

━━━━━━━━━━━━━━━━━━━━━━

Verification :-

${\sf \leadsto 5 \% \: of \: y = 1250}$

Substitute the value of y.

${\sf \leadsto 5\% \: of \: 25000 = 1250}$

Write the percentage as fraction and 'of' as multiplication sign.

${\sf \leadsto \dfrac{5}{100} \times 25000 = 1250}$

Write the fraction on LHS in lowest form by cancellation method.

${\sf \leadsto \cancel \dfrac{5}{100} \times 25000 = 1250}$

Write the obtaining fraction.

${\sf \leadsto \dfrac{1}{20} \times 25000 = 1250}$

Multiply the fractions on LHS.

${\sf \leadsto \dfrac{25000}{20} = 1250}$

Write the fraction in lowest form.

${\sf \leadsto 1250 = 1250}$

So,

${\sf \leadsto LHS = RHS}$

$\:$

Hence verified !!