Math, asked by renukakumarshiva, 7 months ago

Kannan has a fruit shop. He sells 1 dozen banana at a loss of Rs. 2 each because it
may get rotten next day. What is his loss?
22. A submarine was situated at 650 feet below the sea level. If it descends 200 feet,
what is its new position?
how column and diagonal should have the same​

Answers

Answered by bipinsingh7034
1

Answer

Total number of bananas =12

Supposed cost of 1 banana =4 Rs

Cost of 12 bananas =12*4=48

Loss for 1 banana = 2 rupees

Loss for 12 bananas= 2*12=24

Remaining money after loss= 48-24=24 Rs

So

selling price for 12 bananas = 24 Rs

Selling price of 1 banana is =24/12=2 Rs

So net loss will be original price/selling price *100

= 48/24*100

=50% loss

Answered by venkatarajesh75
1

Hi,

Iam a Brainly Academic counselor,

Answer :

1] Sol : As mentioned : He sells the dozen bananas for loss of Rs.2/- ,

So lets think the real price of dozen bananas = y

So , now the cost of the bananas = y - Rs.2/-

= y - 2

Loss[ In percentage ] =  [ real price - selling price ] / selling price x 100%

= y -2 /2 x 100%

= y - 2 x 50

Lets think that y-2 = b

So b x 50 = Loss percentage

= 50b% is his loss ;

2] Sol:  A submarine is situated 650 feet below sea level

It descends 200 feet = 650 + 200 feet

Now the new position of the submarine = 850 feet below the sea level.

hope I made my self clear ,

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