Math, asked by joshijam007, 3 months ago


Kanti sweets wants to place an order for cardboard boxes for packing
sweets. They need two types of boxes ,one with dimensions 25cm x 20cm x 5cm
and another with dimensions 15cm x12 cm x 5cm.For all the overlaps ,5% of
the total surface required is extra. If the cost of cardboard is Rs 10 for
1000cm2
,find the cost of cardboard required for supplying 250 boxes of each
type.








Answers

Answered by diva4589
6

Answer:

Total S.A of bigger box

=2(lb+bh+lh)

=2(25×20+25×5+20×5) cm

2

=2(500+125+100)

=1450 cm

2

⇒For overlapping extra area required =

100

450×5

=72.5 cm

2

∴ Total S.A (including overlaps)

=1450+72.5=1522.5 cm

2

Area of cardboard sheet for 250 such boxes

=(1522.5×250) cm

2

Total S.A of smaller box

=2(15×12+15×5+12×5)cm

2

=630 cm

2

For overlapping area required =

100

630×5

=31.5 cm

2

Total S.A (including overlaps)=630+31.5=661.5 cm

2

Area of cardboard sheet required for 250 such boxes

=250×661.5cm

2

=165375 cm

2

Total cardboard sheet required =380625+165375

=54000 cm

2

⇒Cost of 1000 cm

2

cardboard sheet = Rs.4

⇒Cost of 546000 cm

2

cardboard sheet

= Rs.

1000

546000×4

= Rs. 2184

Answered by neelamrai1002
4

Answer:

Hello army

is any army here ?

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