Question

Kapil travels 30m from a point a towards north and from the south point sachin travels 40m towards east . How far are the two friends from each other now?

Answer 1

Follow the instructions and see the attachment.

The directions of East, West, North and South are mentioned in the picture.

First Kapil travels 30 m from a point " a " towards North.

Now Sachin at the same point "a" is in the Southern direction from Kapil.

So from this point "a" , Sachin travels 40 m East.

Now the distance between them can be determined by using  Pythagoras Law as follows

H^2 = B^2 + P^2               (where D shows the distance between them)

D^2 = (30)^2 + (40)^2

D^2 = 900 + 1600

       = 2500

Taking square root on both sides, we get

D = 50 m

So distance between them is 50m

Answer 2

Kapil travels 30 m from a point " a " towards North.

height=h=30m

and Sachin at the same point "a" is in the Southern direction from Kapil.

So from this point "a" , Sachin travels 40 m East.

base=b=40

Now the distance between them can be determined by using  Pythagoras Law  as follows

(Hypotenus)^2 = (Base)^2 + (height)^2    

base=b=40

height=h=30

d shows the distance between kapil and sachin

d^2 = (40)^2 + (30)^2

d^2 = 1600 + 900

  d^2     = 2500

Taking square root of both sides, we get

distance=d = 50 m

hence  distance  between kapil and sachin is  50m