Question

Kapil wants to fence his rectangular kitchen garden @ Rs. 7 per
metre. If the length of a rectangle is twice its breadth and its perimeter
is 60 m, how much he needs to pay for fencing?

Answer 1

Answer:

length is 20m and breadth is 10m

Step-by-step explanation:

let the length be 2x and breadth be x.

Perimeter = 60m

2 ( l + b ) = 60m

after putting the values

2 ( 2x + x ) = 60m

( 2x + x ) = 60/2 = 30

3x = 30

x = 30/3 = 10

therefore, Length = 2x = 2 × 10 = 20m

Breadth = x = 10m

verifying

perimeter = 2 ( l + b )

= 2 ( l + b )

2 ( 20 + 10 ) = 2 × 30 = 60m.

hope this answer helps you...take care!

Answer 2

$\sf\huge\bold{Answer:}$

Given :

Cost of fencing per metre = Rs 7

the length of a rectangle is twice its breadth i.e

$l = 2b$

perimeter = 60m

To find :

Cost that he needs to pay for fencing.

Length (L)

Breadth(b)

Solution :

Step 1 :

Fencing is done around the kitchen .So,length of wire to be fenced = perimeter of rectangular kitchen

⟶perimeter = 60 m

Step 2 :

Cost of fencing per metre is Rs 7.So,cost of fencing 60 m wire

⟶Cost = cost of fencing 1 m × total length

⟶Cost = Rs 7 × 60

⟶Cost = Rs 420

Cost that he needs to pay for fencing is Rs 420

$\fbox{To find Length and Breadth}$

It is given that

$⟶l = 2b$

Also,formula of perimeter of rectangle

$= 2( l+b )$

and Given perimeter = 60 m

ATQ :According to Question

$⟶2(l + b) = 60...(1)$

Replacing value of L in equation

$⟶2(2b + b) = 60$

$⟶2(3b) = 60$

$⟶6b = 60$

$⟶b = \frac{60}{6}$

$⟶b = 10$

Now,inserting value of b in equation ( 1 )

$⟶2(l + 10) = 60$

$⟶l + 10 = \frac{60}{2}$

$⟶l + 10 = 30$

$⟶l = 30 - 10$

$⟶l = 20$

Hence,

Length = 20 m

Breadth = 10 m