Karan buys a scooty for 40000.The value of scooty depreciates at rate of 10% per annum.Find value after 2 years?
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As the rate of decrease in the cost of the scooter is 10% per year. Therefore, for the first year the cost will reduce by 40000×10/100=400.
Therefore the cost of the scooter after the first year=4000-3600.
Similarly for the second year the cost would decrease by 10%.The cost would be reduce by 3600×10/100=360.Therfore the cost would be equal to 3600-360=3240.
The final answer is rupees 3240.
Therefore the cost of the scooter after the first year=4000-3600.
Similarly for the second year the cost would decrease by 10%.The cost would be reduce by 3600×10/100=360.Therfore the cost would be equal to 3600-360=3240.
The final answer is rupees 3240.
Answered by
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Cost Price of scooty = Rs. 40000
Given that value of scooty depreciates at rate of 10% per annum
Therefore, value of scooty depreciates after first year = 10% of CP
= 10/100 × 40000
= Rs 4000
Therefore, value of scooty after one year =Rs 40000 - Rs 4000 = Rs 36000
Now, value of scooty depreciates after second year = 10% of new value
= 10/100 × 36000
= Rs 3600
Therefore, value of scooty after two years = Rs 36000 - Rs 3600 = Rs 32400
Thank you!! Hope this helps !!
Given that value of scooty depreciates at rate of 10% per annum
Therefore, value of scooty depreciates after first year = 10% of CP
= 10/100 × 40000
= Rs 4000
Therefore, value of scooty after one year =Rs 40000 - Rs 4000 = Rs 36000
Now, value of scooty depreciates after second year = 10% of new value
= 10/100 × 36000
= Rs 3600
Therefore, value of scooty after two years = Rs 36000 - Rs 3600 = Rs 32400
Thank you!! Hope this helps !!
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