Question

Karan is twice as old as Tasha. Five years ago his age was three times Tasha’s age. Find their present ages?​

Answer 1

Answer:

tasha age=10

karan age=20

Step-by-step explanation:

lets take tasha age=x

karan present age=2x

five years ago karans age =2x-5

tasha age five years ago=x-5

five years ago 3 times of tasha age=karan age

=3(x-5)=2x-5

=3x-15=2x-5

=3x-2x=-5+15

=x=10

if x(tasha age)=10

then karan present age=2(10)=20

Answer 2

Step-by-step explanation:

five years ago

x−5=3(y−5)

x−5=3y−15

x−3y+10=0−−−(2)

using eq(1)

2y−3y+10=0

y=10

and x=20

∴ age of karan is 20 and age of tasha is 10