Math, asked by AnitaPawaraur, 6 months ago

Karna was 4 times as old as his son 8
years ago. After 8 years Karna will be
twice as old as his son. What are their
present ages?

please explain step by step ​

Answers

Answered by kurmiamritp
1

Answer:

Let Karan's son's age be x

Karan's Age = 4x

After 8 years

Karan's son's age = x+8

Karan's age = 2(x+8) = 2x+16 or 4x+4(Karan's present age +4)

Now we get 2x+16=4x+4

2x  + 16 = 4x + 4 \\  =  > 16 - 4 = 4x - 2x \\  =  > 12 = 2x \\  =  >  \frac{12}{2}  = x \\ 6 = x

So the value of x is 6

Jai Shree Ram

Similar questions