Question

Karnataka kannada syllabus 8th std 1st chapter kannada
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Answer 1

Explanation:

$Given :</p><p>Mass of the bullet,M = 40gm= 0.04kg</p><p>Mass of the gun,m = 8kg</p><p>Velocity of bullet,u = 800ms⁻¹</p><p>To find :</p><p>The recoil of the gun(V)</p><p></p><p>Solution :</p><p>Initially both bullet and gun are at rest</p><p></p><p>⇒Intial momentum before firing = 0</p><p></p><p>______________________________</p><p></p><p>As no external force acts on the system</p><p></p><p>So According to the law of conservation of Momentum .</p><p></p><p>Total momentum before firing = Total momentum after the firing</p><p></p><p>⇒0 = mu+ Mv</p><p></p><p>⇒MV= -mu</p><p></p><p>⇒8× V= -0.04×800</p><p></p><p>\implies\:V=\dfrac{-0.04\times 800}{8}⟹V= </p><p>8</p><p>−0.04×800</p><p> </p><p> </p><p></p><p>\implies\:V=\dfrac{-4\times800}{100\times8}⟹V= </p><p>100×8</p><p>−4×800</p><p> </p><p> </p><p></p><p>\implies \: V= - 4\: ms {}^{ - 1}⟹V=−4ms </p><p>−1</p><p> </p><p></p><p>Therefore;</p><p></p><p>{\purple{\boxed{\large{\bold{Recoil\:Velocity =-0.4ms{}^{-1}}}}}} </p><p>RecoilVelocity=−0.4ms </p><p>−1</p><p> </p><p> </p><p> </p><p></p><p>⇒The negative sign shows that V and u are in opposite directions i.e ,the gun gives a kick in the backward direction or gun recoils with velocity v.$