Question

karthikeya wanted to make a temporary shelter for street dogs by making a box like structure with tarpaulin that covers all the four sides and the top of the house. how much tarpaulin would be required to make the shelter of height 2.5m with the base dimensions 4m×3m? assuming stitching margin is negligible. which values are depicted in this question?

Answer 1

Sorry I didn't know it.........

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

Let l, b and h be the length, breadth and height of the shelter.

Given:

l = 4m

b = 3m

h = 2.5m

Tarpaulin will be required for the top and four wall sides of the shelter.

Using formula, Area of tarpaulin required = 2(lh + bh)+lb

Put the values of l, b and h, we get

= [2(4 × 2.5 + 3 × 2.5) + 4 × 3] m²

= [2(10 + 7.5) + 12]m²

= 47 m²

• Therefore, 47 m² tarpaulin will be required