Question

Kashvi riding a scooter, moving with a velocity of 72 km h-, applies brakes so that it is stopped in 8 s. Calculate the force exerted by the brakes of the scooter. Given that mass of scooter and Kashvi, taken together, is 170 kg.

Answer 1

Answer: - 425 N

Explanation:

Answer 2

Answer:

Initial velocity(u) = 72 km/hr × 5/18 = 20 m/s

Final velocity (v)= 0 m/s

Time taken to stop the vehicle = 8s

Mass of scooter and Kashvi = 170Kg

We will use the formula F = ma.

a = v - u / t

= 0 - 20/8

= -20/8. Therefore, Retardation =

$= 2.5 \: m\ {s}^{ - 2}$

F = ma

= 170 × -2.5

=425 N (Answer)

Explanation:

First convert the km/hr to m/s.

Negative acceleration = Retardation

Newton's Second Law Formula:-

F = ma

where,

m = mass of the body

a = acceleration produced by the body