Question

kate wanted to buy 2kgs apple.the vendor kept 2kg weight on the right side and weighted 4 apples for that she doubled on the correctness of the balance and placed 2 kg weight on left side and she could weight 14 apples for 2 kgs.ifthe balance was correct.how many apples she could have got.

Answer 1

Hello Friend,
Here's the solution:

Let weight of one apple be x kg.

In both cases, the amount of extra weight put was 2 kg. In first case, it was balanced by 4 apples on left, and in second case, it was balanced by 14 apples on right.

So, we can say that the left side is already heavier than the right side.

Suppose, when nothing is put on any side, the left side is heavier from right side by y kg.

→ In first case, there is two kg weight on right side, and 4 apples on left side.

Now, the load is balanced.

So, total weight on left = total weight on right.

So, y + 4x = 2 -----(1)

(y = extra weight of left side,
4x = weight of apples)

→ In second case, 2 kg was put on right, and 14 apples were put on right.

So, y + 2 = 14x

So, y = 14x - 2 -----(2)

Putting this in (1)
y + 4x = 2
So, 14x - 2 + 4x = 2
So, 18x = 4
So, x = 2/9 kg

Thus, weight of one apple is 2/9 kg.

→ Now, if the balance had been correct, Kate would have received actual 2 kg apples.

So,
Number of apples = (Total Weight)/(Weight of one apple)

So, Numbers of apples = (2)÷(2/9)
So, Number of apples = 9


→ Thus, if the balance had been correct, Kate would have received 9 apples.

I hope I have been able to provide a satisfactory explanation.

Purva
@Purvaparmar1405
Brainly.in