Question

Kaushik is one and half times more efficient than Ravi. Kaushik can do a piece of work in $20$ days. What portion of the total work can both of them together complete in $10$ days? (a)$~\dfrac{3}{10}~~$(b)$~\dfrac{4}{5}$(c)$~\dfrac{9}{10}~~$(d)$~\dfrac{7}{10}$

Answer 1

In 10 days 83.33% of work will be completed if both work together as kaushik will have done 50% ok the work and Ravi would have done 33.33% of he work together it is 83.33%.

Answer 2

The portion of work that can be done in 10 days = 7/10

Given Problem:

Kaushik is one and half times more efficient than Ravi. Kaushik can do a piece of work in 20 days. What portion of the total work can both of them together complete in 10 days?

Given:

Kaushik is one and half times more efficient than Ravi

Kaushik can do a piece of work in 20 days

Tofind:

What portion of the total work can both of them together complete in 10 days?

Solution:

From given data Kaushik can do a piece of work in 20 days  

The work can be done by Kaushik in 1 day = 1/20

Kaushik is one and half times more efficient than Ravi

= kausik is 2 1/2 = 5/2 more efficient than Ravi

The work can be done by Ravi in 1 day = $\frac{1}{20} (\frac{2}{5} )$ =  $\frac{1}{50}$  

The can be done by both together in one day = $\frac{1}{20}$ + $\frac{1}{50}$  

=  $\frac{5+2}{100}$  =  $\frac{7}{100}$  

Therefor the work can be done in 10 days = $10(\frac{7}{100}) = \frac{7}{10}$  

The portion of work that can be done in 10 days = 7/10

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