Math, asked by manupasi9990, 5 months ago

kavita and chameli bought a character pastry kavita at 5 upon and chameli at 3 uopn 7 of it who are more and by how much​

Answers

Answered by amitnrw
0

Given :  kavita and chameli bought a character pastry

kavita at 5/x  

Chaameli 3/7

To Find : who ate more and by how much​

 

Solution:

As Kavita portion is not correctly given we take possible cased

case 1 : kavita at more:

5/ x > 3/7

=> 35 > 3x

=> 3x < 35

=> x  ≤ 11

if x  ≤ 11  then kavita ate more

5/x - 3/7  =    (35 - 3x)/7x  

x = 11  => 2/77

x = 10  =>  5/70 = 1/14

and so on

if chameli  ate more:

5/ x <  3/7

=> 35 < 3x

=> 12 ≤ x

3/7 - 5/x

= ( 3x - 35)/7x

x = 12  => 1/7

x =13  => 4/91

x = 14 => 1/14

Hence depending upon value of x we can get who ate more and how much

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