Question

Kavita is twice as old as Soniya. Five years ago her age was three times Soniya’s age. Find their

present ages.​

Answer 1

Answer:

let age of Kavita be 'x' and age of Shriya be 'y'

then according to question x=2y−−−(1)

and five years ago

x−5=3(y−5)

x−5=3y−15

x−3y+10=0−−−(2)

using eq(1)

2y−3y+10=0

y=10

and x=20

∴ age of Kavita is 20 and age of Soniya is 10

Step-by-step explanation:

Mark as Brainliest❣️ (^≗ω≗^)

Answer 2

Answer:

let age of Arjun be

′

x

′

and age of Shriya be

′

y

′

then according to question x=2y−−−(1)

and five years ago

x−5=3(y−5)

x−5=3y−15

x−3y+10=0−−−(2)

using eq(1)

2y−3y+10=0

y=10

and x=20

∴ age of Arjun is 20 and age of Shriya is 10