Kavitha invested ₹10,000 at an interest rate of 10% p.a. compounded annually. What amount she will get after the end of 2 years
Answers
Answered by
1
Answer:
interest=
100
p∗r∗t
p = principal amount , r = rate , t = time
interest=
100
10000∗5∗1
interest = RS. 500
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Answered by
3
Step-by-step explanation:
A = P [ 1 + r/100 ]ⁿ
A = 10000 [1 + 10/100]²
A = 10000 [11/10]²
=> (10000 × 11 × 11) / 100
=> 100 × 121
=> Rs 12100
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