Question

Kaya is riding her dirt bike eastward on a dirt road. She spots a pothole ahead.
Kaya slows her car from 14.0 m/s to 5.5 m/s in 6.0 s. What is her acceleration?

Answer 1

Initial velocity of the particle = 14 m/s

Final velocity = 5.5 m/s

Time taken = 6 s

We know,

$\boxed{a = \frac{∆v}{∆t} \ or \ \frac{v - u}{t}}$

∴ Acceleration in this condition = (5.5 m/s - 14 m/s)/(6 s)

⇒ a = (- 8.5 m/s)/(6 s)

⇒ a ≈ 1.417 m/s².

∴ Acceleration, in this case, of Kaya was of - 1.4 m/s².

More:- (all equations are in usual terms)

In a straight or any path,

• $v = \frac{s}{t}$

In case of motion in a circular path:-

(a little modification)

• $v = \frac{2 \pi r}{t}$