Question

Kayden is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove at a constant speed to get to the safe zone that was 160160160 meters away. After 333 seconds of driving, she was 858585 meters away from the safe zone. Let yyy represent the distance (in meters) from the safe zone after xxx seconds. Complete the equation for the relationship between the distance and number of seconds.

Answer 1

Answer:

Given:

The variable d models Rachel's distance from her exit (in meters) t seconds after the cameras began recording the stunt. d = - 38t + 220

To find:

What is Rachel's speed?

Solution:

From given, we have,

The expression that represents the Richel's distance is given by,

d = - 38t + 220

where, d represents the distance in meters

           t represents the time in seconds

We know that, speed = distance by time.

Therefore, we need to differentiate the given equation w.r.t to time to find the speed.

Hence, we have,

d/dt (d) = d/dt [- 38t + 220]

| d/dt (d) | = | - 38 + 0 |

s =  d/dt (d) = 38 m/s

Therefore, the speed of Rachel is 38 m/s.

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Step-by-step explanation: