Question

Kc for H2+I2 <->2HI at 700k is 49 than kc for HI<->1/2 H2+1/2 I2 is

Answer 1

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Here's your answer...

$Kc = \frac{ {(HI)}^{2} }{(H)(I)} = 49$

For the second equation,
$K = \frac{ {(H)}^{ \frac{1}{2} } {(I)}^{ \frac{1}{2} } }{(HI)} \\ = \frac{1}{ \sqrt{Kc} } \\ = \frac{1}{ \sqrt{49} } \\ = \frac{1}{7}$

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