KCIO3 generates 1.5 grams of oxygen. So how much KCI will be in this process.
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KClO3. = KCL + 3/2 O2
122.5 GM OF KCLO3 GIVES 48 GM
1.5GM OXYGEN TO FORM HOW MUCH KCLO3 REQUIRED?
122.5x1.5/48 = 3.82 GM of KCLO3
122.5 GM of kclo3 FORMS 74.5GM KCL
3.82 x74.5/112.5 =2.52 gm
bony443:
but why you take KCl weight as 58.5
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