Question

KCl and I2 are both solids at room temperature. Which substance will dissolve in H2O and which substance will dissolve in CCl4. Give an explanation for your choice ​

Answer 1

Answer:

All the substances listed are solids at room temperature. Which substance has a simple molecular structure? A. Sodium. B. Iodine

Answer 2

Potassium chloride$(KCl)$ will be soluble in water$(H_2O)$ and iodine $(I_2)$ will be soluble in carbon tetrachloride $(CCl_4)$

Explanation:

• Whenever the solubility of a substance has to be determined, we need to look into the type of intermolecular forces, the solute and the solvent possess.
• Potassium chloride $(KCl)$ is made up of ions or it possesses dipole moment. Hence, it will be soluble in a polar solvent like water$(H_2O)$
• Iodine $(I_2)$ is made up of the same atoms, thus, there is no electronegativity difference in their bonds, and the molecule is non-polar, and possesses no dipole moment. So, it will be soluble in a solvent that does not possess a dipole moment like carbon tetrachloride$(CCl_4)$