Question

KClO3 decomposes to give KCl and O2 . Calculate the mass and volume of O2 produced by 50g KClO3​

Answer 1

Answer:

Your question is...

KClO3 decomposes to give KCl and O2 . Calculate the mass and volume of O2 produced by 50g KKClO3...

My answer is....

2kclo3 = 2kcl + O2

2kclo3 = 2 × 122.5 & O2 = 3 × 16

245 gram gives 48 grams O2

Then,

50 grams should give X grams....

•°• X = 50 × 48 / 245

X = 9.79

So, Your answer is....9.79 grams...

Now you can find volume by yourself very easily...

Hope it helps....☺️☺️☺️

Please mark me as a brainlist....

Answer 2

The mass of the O₂ produced is equal to 19.84 grams and the volume of the O₂ produced is equal to 13.89 litres.

Given:

The mass of KClO₃ present = 50 g

To Find:

The mass and volume of the O₂ produced.

Solution:

→ KClO₃ decomposes to give KCl and O₂.

                                         2KClO₃ → 2KCl + 3O₂

→ 2 moles of KClO₃ decompose to give 2 moles of KCl and 3 moles of O₂.

→ The molar weight of KClO₃ is 122.55 grams.

∵ 1 mole of KClO₃ has a mass of 122.55 grams.

$\boldsymbol{\therefore Number\:of\:moles\:in\:50 \:grams \:of\: KClO_{3} =\frac{50}{122.55}=0.41\:moles}$

→ Since 2 moles of KClO₃ produce 3 moles of O₂.

∴ No. of moles of O₂ produced by 0.41 moles of KClO₃ = $\boldsymbol{\frac{3}{2}\times0.41=0.62}$

∴ 50 grams of KClO₃ produces 0.62 moles of O₂.

→ One mole of O₂ has a mass equal to 32 grams and a volume equal to 22.4 litres.

∴ The Mass of 0.62 moles of O₂ = 0.62 × 32 = 19.84 grams

∴ The volume of 0.62 moles of O₂ = 0.62 × 22.4 = 13.89 litres

Therefore the mass of the O₂ produced is equal to 19.84 grams and the volume of the O₂ produced is equal to 13.89 litres.

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