Chemistry, asked by SRINEEVAS2996, 11 months ago

KClO4 may be prepared by means of the following series of reactions- Cl2 + 2KOH > KCl + KClO + H2O 3KClO > 2KCl + KClO3 4KClO3 > 3KClO4 + KCl how much Cl2 is needed to prepare 400g KClO4 by the above sequence? (K= 39, Cl=35.5, O=16, H=1)

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Answered by RajaDhanish

1

Answer:

10.67 l is the answer for your question

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