Question

KE=1/2mvsquare check it is dimensionally correct or not?​ pls tell me quick​

Answer 1

Answer:

$The equation is correct.</p><p>Explanation:</p><p>Given that,</p><p>The equation is</p><p>\dfrac{1}{2}mv^2=mgh21mv2=mgh</p><p>Taking left hand side</p><p>Kinetic energy K.E=\dfrac{1}{2}mv^2K.E=21mv2</p><p>Here, \dfrac{1}{2}21 is constant</p><p>m = mass</p><p>v = velocity</p><p>Dimension formula of kinetic energy</p><p>\dfrac{1}{2}mv^2=[M][L^2T^{-2}]21mv2=[M][L2T−2]</p><p>Taking right hand side</p><p>Dimension formula of potential energy</p><p>Potential energy P.E = mgh</p><p>Here, g = acceleration due to gravity</p><p>h = height</p><p>m = mass</p><p>mgh=[M][LT^{-2}][L]mgh=[M][LT−2][L]</p><p>mgh=[M][L^2T^{-2}]mgh=[M][L2T−2]</p><p>The Left hand side equal to right hand side.</p><p>Hence, The equation is correct.</p><p>$