KE of a body is increased by 44%.What is the percent increase in the momentum?
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Relation between kinetic energy (K) and momentum (p) is
K = p² / (2m)
K2 / K1 = (p2 / p1)^2
p2 / p1 = sqrt(K2 / K1)
(p2 / p1) - 1 = sqrt(K2 / K1) - 1
Δp / p1 = sqrt(K2 / K1) - 1
Δp = p1 × [sqrt(K2 / K1) - 1]
= 100 × [sqrt(144 / 100) - 1]
= 20
Momentum is increased by 20%
K = p² / (2m)
K2 / K1 = (p2 / p1)^2
p2 / p1 = sqrt(K2 / K1)
(p2 / p1) - 1 = sqrt(K2 / K1) - 1
Δp / p1 = sqrt(K2 / K1) - 1
Δp = p1 × [sqrt(K2 / K1) - 1]
= 100 × [sqrt(144 / 100) - 1]
= 20
Momentum is increased by 20%
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