Physics, asked by Samariagomez8228, 1 year ago

KE of a body is increased by 44 % what is the percentage increase in momentum

Answers

Answered by Anonymous
4
have earlier shown the relation between kinetic energy and momentum in my ans of question of the same type which can be seen from my answers.

The relation is

Ke=p^2÷2m

Now,

Ke'=ke+44%ofke

=Ke+0.44ke

Ke' =1.44ke

P'^2÷2m=1.44p^2÷2m

P'2=1.44p^2

P'=1.2p

Now %increase in momentum,

={(P'-p)÷p}×100

={(1.2p-p)÷p}×100

={0.2p÷p}×100

=0.2×100

=20%

Hence momentum will increase by 20%

Thanks for reading and upvoting…

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