Question

KE of lg a body A is double than the
body B Find the ratio of theire masses if
both the bodies au moving with same
velocity​

Answer 1

Answer:

your answer is

Explanation:

The kinetic energy of rotation is given by 21Iω2.

Since the kinetic energy of rotation is same, 

IAωA2=IBωB2

⟹ωBωA=IAIB

The ratio of the angular momentum becomes,

LBLA=IBωBIAωA

=IBIA<1

⟹LB>LA

hope it helps you

Answer 2

Answer:

2:1

Explanation:

KE = mv^2/2.......(i)

Let the velocity of both the bodies be v and the kinetic of energy of body B be x.

Let the mass of body A be M and that of body B be m.

therefore, kinetic energy of body a will be 2x.

(KE of body A)/(KE of body B) = (Mv^2/2)/(mv^2/2)

2x/x = (Mv^2/2)/(mv^2/2)

on RHS, since value of v^2/2 is common for both denominator and numerator, they get cancelled.

therefore, 2x/x = M/m

on LHS, x gets cancelled

therefore, M/m = 2/1

therefore, M:m = 2:1