Question

KE per unit volume is​

Answer 1

Answer:

KE of one molecule 3/2KbT

Explanation:

As we know that for molecule.....

PV = 1/3mNAv²......

where m = mass of molecule

NA = avagadro number

v= velocity of molecule

From Ideal gas equation....

PV = nRT.....

for one mole i.e n = 1

PV = RT

now put the value of PV in equation (1)

RT = ⅓mNAv²

3RT = mNAv²..........(2)

now equation 2 multitply with 1/2

now equation 2 multitply with 1/23/2RT = 1/2mv².NA

3/2RT = KE of one molecule.NA

Since KE of one molecule = 3/2RT/NA

As R/NA = Boltzman constant = Kb

KE of one molecule = 3/2 KbT