Keeping his speed the same, John takes 1{frac(1/2)} times as much time to jog once along the outer edge of the circular track shown here as compared to the inner edge.
What is the width of the track if the radius of the inner edge is 24 m?
A
36 m
B
24 m
C
15 m
D
12 m
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Answer:
36
Step-by-step explanation:
we need to find out circumstances of both circles,
given that,
speed is constant. let S
time for inner journey ,T1 = 2pi24/S
time for outer edge journey T2 = 2piR/S
3/2 of T1 = T2
3/2 2pi24 = 2piR. (speed cancelled on both side)
36=R
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