Question

Keeping the length of a simple pendulum constant, will the time period be the same on all planets? Support your answer with reason.

Answer 1

Time period is given by, $T=2\pi\sqrt{\frac{l}{g}}$

Where l is length of simple pendulum, g is acceleration due to gravity and T is time period.

A/c to question, keeping the length of a simple pendulum constant . Then time period is inversely proportional to square root of acceleration due to gravity.

But we know, acceleration due to gravity varies from planet to planet. So, time period doesn't be the same in all planets.

Answer 2

Answer:

Acceleration due to gravity in depth d from the earth's surface is given by, g=g_0\left(1-\frac{d}{R}\right)g=g

0

(1−

R

d

)

where g_0g

0

is the acceleration due to gravity on the earth's surface and R is the radius of the earth.

We have to find acceleration due to gravity at the centre of the earth.

at centre of the earth, depth = radius of earth's surface . e.g., d = R

Hence, g = g_0\left(1-\frac{R}{R}\right)g

0

(1−

R

R

)

g = 0

Hence, value of g will be zero at the centre of the earth.