Question

Keeping the mass constant if the distance between two objects is doubled,then the force of attraction between them will

Answer 1

gravitational force between two point mass is given by formula

$F_g = \frac{Gm_1m_2}{r^2}$

now here if mass is constant while the distance between the two mass is doubled then the gravitational force between them

$F_g' = \frac{Gm_1m_2}{(2r)^2}$

so on solving above

$F_g' = \frac{Gm_1m_2}{4r^2}$

so here this force of gravitation is compared with the previous force

$F_g' = \frac{F_g}{4}$

so here the gravitational for is decreased by 4 times