keeping the potential difference constant if the resistance of a circuit is double .By what factor does the current change in the circuit
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According to ohm's law
R =v/I...............(1) ( R=resistance, V=voltage , I =current )
let I' be the current when Resistance become double
2R = V/I' ............(2) (V is constant)
dividing equation (2) by (1)
R/2R= (V/I)/V/I'
1/2=I'/I
I=2I'
I/2=I'
Current through conductor become half
aahanas957:
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