Question

keeping the potential difference constant ,the resistance of a circut is double .by how much does the current change?​

Answer 1

Explanation:

Current become half because current inversely proportional to resistance

Answer 2

Answer:

Current is halved.

Explanation:

By Ohm's Law,

V = IR

where,

V - Potential Difference

I - Current

R - Resistance

Given,

V - Constant

Let the initial value of resistance be R. For this resistance, let the current in the circuit be $I$.

Then, by Ohm's law,

V = IR ..............................................[1]

Now, when the resistance is doubled [R--> 2R], let the current in the circuit be $I$' .

By Ohm's law,

V = I'(2R)

=> V = 2I'R ..............................................[2]

From equations 1 and 2

Since LHS are equal, their RHS are also equal.

=> IR = 2I'R

Cancelling R from both sides,

=> I = 2I'

=> I' = I/2

Hence the current in the circuit is halved when the resistance is doubled under constant potential difference.

HOPE IT HELPS