Question

Keeping the velocity of projectile constant the angle of projection is increased by 90 the horizontal range of the projectile is

Answer 1

Explanation:

Horizontal Range, R=

2g

u

2

sin2θ

R∝ sin2θ

sin2θ increases till 2θ=90

0

i.e θ=45

0

Hence, Range R increases till 45

0

then decreases.